Class,
PS9 is online in case you did not get a paper copy in class. Also, there is a correction in problem 4. Where it refers to "problem 5" it should read instead "problem 3".
MSS
This blog serves as a central repository for information related to thermodynamics and statistical mechanics classes I teach at the University of California Santa Barbara, Department of Chemical Engineering. Comments are limited to undergraduate and graduate chemical engineering students at UCSB.
Friday, November 28, 2008
Monday, November 24, 2008
Office hours tomorrow
Dear class,
I will hold office hours tomorrow immediately after our class, at 1:30pm.
MSS
I will hold office hours tomorrow immediately after our class, at 1:30pm.
MSS
Sunday, November 23, 2008
TA Office hour
Due to the change of PS due date, I think I need to change TA office hour to Monday after class, 3:00-4:00.
Is it good for you?
Wednesday, November 19, 2008
Hint for 2.2 on midterm
You are looking for the variation of T with V in a certain kind of process. Thus, you might want to consider a derivative of the form (dT/dV).
MSS
MSS
Thursday, November 6, 2008
Extra office hours
If there are further questions about PS6, I will be available in my office from 3-4pm today (11/6) to answer questions.
MSS
MSS
Monday, November 3, 2008
Correction to today's lecture
I inadvertently omitted a part of an equation derived today in class.
Recall that we had for the pure-component chemical potential:
d(mu/T)/dT = -h / T^2
If we assume h is constant with temperature, we can integrate from Tm to T, where Tm is the pure melting temperature, to get:
mu(T)/T - mu(Tm)/Tm = h * (1/T - 1/Tm)
Or, rearranging
mu(T) = h * (1 - T/Tm) + mu(Tm) * (T/Tm)
In class, I left off the rightmost term. When we apply this equation to both the pure liquid and crystal and take the difference, we get:
mu_L(Tm) - mu_X(Tm) = (h_L - h_X) * (1 - T/Tm) + [mu_L(Tm) - mu_X(Tm)] * (T/Tm)
However, mu_L(Tm) = mu_X(Tm) by the conditions for phase equilibrium at Tm, so the rightmost term vanishes.
MSS
Recall that we had for the pure-component chemical potential:
d(mu/T)/dT = -h / T^2
If we assume h is constant with temperature, we can integrate from Tm to T, where Tm is the pure melting temperature, to get:
mu(T)/T - mu(Tm)/Tm = h * (1/T - 1/Tm)
Or, rearranging
mu(T) = h * (1 - T/Tm) + mu(Tm) * (T/Tm)
In class, I left off the rightmost term. When we apply this equation to both the pure liquid and crystal and take the difference, we get:
mu_L(Tm) - mu_X(Tm) = (h_L - h_X) * (1 - T/Tm) + [mu_L(Tm) - mu_X(Tm)] * (T/Tm)
However, mu_L(Tm) = mu_X(Tm) by the conditions for phase equilibrium at Tm, so the rightmost term vanishes.
MSS